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And the answer is.......

 
 
Reply Sat 25 Mar, 2017 02:49 pm
A math teacher gave his class two tests. 25% of the class passed both tests and 42% of the class passed the first test. What percent of those who passed the first test also passed the second test?
Chew on that one for a bit.... Rolling Eyes Question
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Type: Question • Score: 3 • Views: 708 • Replies: 10

 
centrox
 
  1  
Reply Sat 25 Mar, 2017 03:16 pm
Are you serious?
0 Replies
 
timur
 
  1  
Reply Sat 25 Mar, 2017 03:18 pm
This is a 100% complicated question, isn't it?
0 Replies
 
Blickers
 
  1  
Reply Sat 25 Mar, 2017 03:33 pm
(25% ÷ 42%) = the percentage of those who passed the first test who also passed the second.
0 Replies
 
McGentrix
 
  -1  
Reply Sat 25 Mar, 2017 03:43 pm
@visceral,
P=(probability of something)
A=students that passed first test
B=students that passed both tests

So, using conditional probability,

P(A and B) = P(A)*P(B/A)
Divide both sides by P(A)
P(A and B)/P(A)=P(A)*P(B/A)/P(A)
Cancel **** out
P(A and B)/P(A)=P(B/A)
Commute that ****
P(B/A)=P(A and B)/P(A)

So, figure that **** out... 60%
visceral
 
  1  
Reply Sat 25 Mar, 2017 06:27 pm
@McGentrix,
bingo...Smile
Blickers
 
  1  
Reply Sat 25 Mar, 2017 07:23 pm
@visceral,
Quote visceral:
Quote:
Re: McGentrix
bingo... Very Happy


How come I don't get a bingo? 25% ÷ 42% = 59.52%.

Sheesh, I handed you the answer. Don't you want to do at least part of your homework yourself?
ekename
 
  2  
Reply Sat 25 Mar, 2017 09:17 pm
@visceral,
Tough crowd in tonite.

0 Replies
 
visceral
 
  3  
Reply Sun 26 Mar, 2017 12:34 am
@Blickers,
my ap0logies to you...you get a "bingo" too....... Razz
izzythepush
 
  1  
Reply Sun 26 Mar, 2017 09:10 am
A million percent, sorry a billion, (typo.)
0 Replies
 
Blickers
 
  2  
Reply Sun 26 Mar, 2017 11:20 am
@visceral,
Quote visceral:
Quote:
my ap0logies to you...you get a "bingo" too....... Razz

Thank you. I feel much better now. Laughing
0 Replies
 
 

 
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