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Probability of a random stop by an officer in .4 of a mile from a home

 
 
Reply Thu 26 Nov, 2015 08:53 pm
If I was driving from my house at night .4 of a mile which Google Maps says it takes 2 minutes to drive. There are 5 cross streets down the road which an officer could of been siting at and pulled out behind me. ( yet this would have to be .3 of a mile and less then two minutes )
So in less then two minutes the officer will claim he saw my tags were expired and pulled me over..

What is the probability of this event being random?

I am trying to prove in court that the officer had seen my expired tags in the day and was sitting out there stalking me waiting for me to pull out.

Thank you
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Type: Question • Score: 1 • Views: 349 • Replies: 4

 
neologist
 
  2  
Reply Thu 26 Nov, 2015 09:04 pm
@hdpeterson75,
But your tags were expired right? So what difference does it make when he saw them?
He may have driven by earlier and noted the expiration, so, when you decided to drive, it was a chip shot for him. He didn't need to lie in wait, a proposition most judges would find unlikely.

The solution?

Pay for the tags. Go to court. And, beg for mercy. In Washington state, that will usually cut you enough slack for reduced or zero fine.
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ehBeth
 
  1  
Reply Thu 26 Nov, 2015 09:06 pm
@hdpeterson75,
hdpeterson75 wrote:
So in less then two minutes the officer will claim he saw my tags were expired and pulled me over..


the joy of the onboard computer in police vehicles

I'm not sure if they key in the plates or if there's an automatic plate reader but it takes literally a second or two for them to catch expired tags
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ehBeth
 
  2  
Reply Thu 26 Nov, 2015 09:07 pm
@hdpeterson75,
hdpeterson75 wrote:
I am trying to prove in court that the officer had seen my expired tags in the day and was sitting out there stalking me waiting for me to pull out.


that's an entertaining approach
neologist
 
  4  
Reply Thu 26 Nov, 2015 09:10 pm
@ehBeth,
Heh.
I imagine the judge at his next poker night . . .
"You know what some idiot claimed . . . .?"
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