Reply Sun 15 Feb, 2015 07:03 pm
An acre of land is to be planted with trees. The trees are to be placed 4 feet apart. Determine number to trees.

What is known:

An acre is to be planted with trees.
The trees are to have a 4 foot distance between trees.

Want to know:

Number of trees.

An acre = 43,450 square feet, 4840 square yards.

43560 / 4 = 10,890 trees.

Where did I make the error(s) ?

NOT a homework question.
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Type: Question • Score: 1 • Views: 1,154 • Replies: 34
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neologist
 
  1  
Reply Sun 15 Feb, 2015 07:58 pm
@Randy Dandy,
Can you see where the number 10,890 represents trees 2 feet apart?
Randy Dandy
 
  1  
Reply Sun 15 Feb, 2015 08:10 pm
@neologist,
No.
leball
 
  1  
Reply Sun 15 Feb, 2015 09:05 pm
@Randy Dandy,
try 10862 trees
Randy Dandy
 
  1  
Reply Sun 15 Feb, 2015 11:01 pm
@leball,
Please explain your answer.
0 Replies
 
neologist
 
  1  
Reply Mon 16 Feb, 2015 01:39 am
@Randy Dandy,
Take a small corner of the acre with only four trees, a square four feet each side. How many such squares in your acre?

Rembering that each of thse squares has trees in common with its neighbors, can you see how the problem lays out?

This is not an algebra problem
It's an Engliish problem
Randy Dandy
 
  1  
Reply Mon 16 Feb, 2015 09:45 am
@neologist,
"Take a small corner of the acre with only four trees, a square four feet each side. How many such squares in your acre?"

16 square feet.
neologist
 
  1  
Reply Mon 16 Feb, 2015 10:12 am
@Randy Dandy,
Randy Dandy wrote:
16 square feet.
How many trees are counted in each 16 square foot area?
Randy Dandy
 
  1  
Reply Mon 16 Feb, 2015 11:29 am
@neologist,
4 ?
neologist
 
  1  
Reply Mon 16 Feb, 2015 01:06 pm
@Randy Dandy,
Hmm.
Imagine the sqaure in the upper right corner.
Imagine the tree in the upper right corner of that square.
That tree belongs to that square.
The trees in the 3 other corners belong to adjacent squares.

There are other ways to visualize. I suggest drawing a sketch.
But the bottom line is each tree needs 16 square feet
Randy Dandy
 
  1  
Reply Mon 16 Feb, 2015 03:15 pm
@neologist,
Let T represent Tree

T ---- 4' ---T

4' 4'

T --- 4'-- T

I still don't grasp it.
raprap
 
  1  
Reply Mon 16 Feb, 2015 04:43 pm
@Randy Dandy,
go both ways---every tree needs to be 4 foot from another tree in two (no one) dimension.

Rap
Randy Dandy
 
  1  
Reply Mon 16 Feb, 2015 04:50 pm
@raprap,
I don't understand.
0 Replies
 
dalehileman
 
  1  
Reply Mon 16 Feb, 2015 05:02 pm
@Randy Dandy,
Randy does the shape of the tract matter or the arrangement

...and in the case rearrangement matters, are you looking for the range, a min or a max

Quote:
Where did I make the error(s) ?
What was it you consider in possible error
Randy Dandy
 
  1  
Reply Mon 16 Feb, 2015 05:25 pm
@dalehileman,
"Randy does the shape of the tract matter or the arrangement" Just the 4 feet apart.

" ...and in the case rearrangement matters, are you looking for the range, a min or a max" Just the number of trees.

"What was it you consider in possible error" Seems like a large number for just an acre.
0 Replies
 
neologist
 
  1  
Reply Mon 16 Feb, 2015 05:57 pm
@Randy Dandy,
If it's a perfect square of 208' each side
You will have 208/4=52 rows of 52 trees each
Randy Dandy
 
  1  
Reply Mon 16 Feb, 2015 06:28 pm
@neologist,
Thanks.

I found an answer to the same problem in another location:

2722.5

How was this answer obtained ?

"This is not an algebra problem
It's an Engliish problem" Why ?
dalehileman
 
  1  
Reply Mon 16 Feb, 2015 06:35 pm
@neologist,
But if you should shift 'em over a bit so they're not centered, would the answer be 208 smaller

And what if the proportions aren't multiples of 4 ft

Randy won't specify
neologist
 
  1  
Reply Mon 16 Feb, 2015 06:36 pm
@Randy Dandy,
It relies on you using your language understanding to develop a mental picture of the problem.
0 Replies
 
neologist
 
  1  
Reply Mon 16 Feb, 2015 06:39 pm
@dalehileman,
Well, there a few schematics that give answers with fractions of trees.
The sides of a square acre are 208 feet + inches. So rounding to 2704 seems reasonable.
 

 
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