diannemartin
 
Reply Tue 9 Sep, 2014 12:30 pm
a small community consists of 10 men each of its home has 3 sons. if 1 man and 1 of his sons are to be chosen as father & son of the year. how many different choices are possible?
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Type: Question • Score: 1 • Views: 2,022 • Replies: 2
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engineer
 
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Reply Tue 9 Sep, 2014 12:31 pm
@diannemartin,
3x10 = 30
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wehliyaaka
 
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Reply Tue 16 Sep, 2014 06:12 am
@diannemartin,
Since each man has 3 sons then 10 men can have a total of 30 Sons
First man and his 1st son then first man and his 2nd son and first and his 3rd son so and so on until the last man and then multiply al of these
So it will be 3x3x3x3x3x3x3x3x3x3
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