Area

A field, rectangular whose length is twice the width, is enclosed by x yards of fencing. Calculate area in terms of x.

What is known:

The field is a rectangle.
Length is twice width. Then L=2W, right?
Enclosed by x yards of fencing.

Want to know:

Area in terms of x.


Perimeter (X) = 2L + 2W or X = 2 (2W) + 2W = 6W
Area = L x W or A = (2W)(W) = 2W^2

How do I proceed from this point?

if X=6W, and
A=2W^2, then
W= root (A/2)
Substituting
X = 6 root (A/2)