@dalehileman,
The purpose of dual circuits is mostly so that you don't have to re-solve an entire array of mesh or nodal equations on another circuit when it's the dual of one you've already solved (it's already solved for you, you just need to switch the dual quantities).
I've never had to use this technique outside of the class I learned it in (at least not this way); however, this general idea of the duality of electricity and magnetism is very useful in developing circuits where you need an opposite response or the same response in a different quantity (voltage vs. current). For example, high pass filter vs. low pass filter (these are not necessarily dual circuits - they just exemplify the dual nature of the elements).
As far as reacting the same way, the answer appears to be
Quote:Dual circuits react the same way!
BUT, you must understand that it is a similar response under
dual conditions (current response to voltage response).
For instance, if you were using a
voltage source and you were looking at the output
voltage over some element, then the dual response would be the same as long as you were looking at the output
current through the dual of the same element mentioned in the voltage driven source (again, remember that the dual of a voltage source is a
current source).
Quote:To put it simply, the equations are exactly the same, but the variables are switched with their dual element. Not one single numerical value will actually change (the steps for determining the dual should prove this), but what you're looking at will change.
Using a dual is more useful when using variables (R, L, C, etc.) as a means to quickly obtain the solution of a circuit - from there, the desired values are chosen for the desired response. Often, the dual of one specific circuit will not perform as well as the other, but this comes down to how each element is manufactured and the typical values, tolerances, and power ratings of each device.
And just in case it isn't clear, when you solve for a dual circuit (assuming it has a dual) you must change
every element in the network; otherwise, you've altered the response of the circuit.