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Probability

 
 
Reply Sun 7 Oct, 2012 07:08 am
A study was conducted among members of a health insurance whose policies
require a second opinion on the advisability of surgery. Of the members whose
doctors advised them to have surgery, 20% were informed by a second doctor
that no surgery was needed. Of those, 70% took the second opinion and did not
go through with the surgery. Of the members who were advised to have surgery
by both doctors, 95% went through with the surgery. What is the probability that a person who had surgery was advised to do so by the second doctor?

Can be solved by bayes' theorem??
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Type: Discussion • Score: 1 • Views: 2,098 • Replies: 1
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markr
 
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Reply Sun 7 Oct, 2012 01:02 pm
@angelrocksvid,
.8*.95/(.8*.95 + .2*.3) = 0.9268
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