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Math 101: Dividing trinomials by binomials

 
 
Reply Fri 6 Nov, 2009 06:40 pm
(15a^4-3a^3+4a^2+4) divided by (3a^2-1)

15a^4 = 15a to the 4th power. etc.

it's hard to write all the work out but I'm getting stuck at the -3. I can do synthetic division but I get stuck at the 4.
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Type: Question • Score: 0 • Views: 7,315 • Replies: 3
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oolongteasup
 
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Reply Fri 6 Nov, 2009 08:14 pm
@brokencdplayer,
factorise the numerator and denominator then simplify
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engineer
 
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Reply Fri 6 Nov, 2009 08:15 pm
@brokencdplayer,
Be sure to put zeros in for the missing powers of a

(15a^4 - 3a^3 + 4a^2 + 0a + 4) / (3a^2 + 0a -1)

It didn't divide evenly. I ended up with a remainder of (-a+7)
oolongteasup
 
  1  
Reply Fri 6 Nov, 2009 08:29 pm
@engineer,
i kinda guessed

http://www.purplemath.com/modules/polydiv3.htm
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