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Thu 17 Sep, 2009 06:00 am
why 0! is equal to 1?
Consider the (trivial) fact that factorials can be calculated by recurrence:
n! = (n-1)! x n
Rearranging:
(n-1)! = n!/n
And setting n=1 we can deduce:
0! = (1-1)! = 1!/1 = 1/1 = 1
Also, it can be said that an empty set can only be ordered one way, so 0! = 1.