Member since March 3, 2006

Triggy18

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Triggy18
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Mon 6 Mar, 2006 02:09 pm - never mind, you got the same answer. Ok thanks. (view)
Mon 6 Mar, 2006 02:07 pm - [quote]Pythagorean thm sin²(y)+cos²(y)=1 sin(y)=2(sin²(y)-1) [/quote] rap, That should be 1 - sin^2y not sin^y -1 (cos^2(y) + sin^2(y) = 1 so cos^2(y) = 1 - sin^2(y) (view)
Sun 5 Mar, 2006 02:15 pm - Problem with number 2.4 The answer is 112 degrees but how do they get there? -Thanks[img]http://i22.photobucket.com/albums/b312/Red888/TrigGraph0001.jpg[/img] (view)
 
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