Wed 27 Mar, 2013 06:59 pm - Well, I know that the probability must increase as we increase the number of trials, so we must find a greater probability than the .5064 we started with for a single trial, which leaves only... (view)
Wed 27 Mar, 2013 06:06 pm - Yes, I ran your formula and it provides the same answer as delivered from the online binomial calculator I referenced for "Cumulative Probability: P(X > 1)" which is good.
Here is... (view)
Wed 27 Mar, 2013 04:52 pm - That is exactly what I want to confirm. So let's say each match involves two unrelated events, with the probability of event A ocurring at 48% and event B at 66%. When you run the formula you... (view)
Wed 27 Mar, 2013 04:20 pm - Thanks. Wish I had given a better explanation from the start:)
What I could have said is that two players engage in challenges where each tosses a pair of dice in repeated matches until ony one... (view)
Wed 27 Mar, 2013 04:09 pm - Yes, but it is not the game that ends, just that challenge is resolved and the outcome has consequences for the two players within the larger game. (view)
Wed 27 Mar, 2013 03:58 pm - No, and that would be a silly game. These challenge matches and uneven probabilities for the players involved are one mechanism in a larger game, and I have not given all that background here. I am... (view)
Wed 27 Mar, 2013 03:53 pm - It's not that the dice have memory, but it is like a series of coin tosses. The probability of heads or tails for each toss is always the same, but for a specific number of tosses in a series... (view)
Wed 27 Mar, 2013 03:02 pm - Well, I am not completely describing what is actually happening in the game because it would take time, and the example I gave of a challenger and defender respectively trying for a 6 and a 7... (view)
