Mon 18 Mar, 2013 02:47 am - Thanks for your reply
I've been pointed to this forum thread, which talks about the same issue. There's no way around integrating, it seems.
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Fri 15 Mar, 2013 04:12 am - Hi,
Say we have three runners: A, B and C, and we have the probability of each runner beating each individual opponent:
A before B: 0.68
A before C: 0.42
B before A: 0.32
B before C:... (view)