Member since March 15, 2013


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Probability, Independent, Runners, Race, Odds
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Mon 18 Mar, 2013 02:47 am - Thanks for your reply I've been pointed to this forum thread, which talks about the same issue. There's no way around integrating, it seems. (view)
Fri 15 Mar, 2013 04:12 am - Hi, Say we have three runners: A, B and C, and we have the probability of each runner beating each individual opponent: A before B: 0.68 A before C: 0.42 B before A: 0.32 B before C:... (view)
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