Sat 26 Jul, 2014 02:05 am - OK great
1) I have also questioned this, but now believe it is relevent for this question (i.e. when assortment refers to considering whether there is an underlying propensity) as if none of this... (view)
Fri 25 Jul, 2014 12:26 am - part 2: OK fair enough, maybe ignore the permutation part , thats just added complications. I suppose the real question is simply: when given lots of groups of individuals (just like the canteen... (view)
Thu 24 Jul, 2014 01:11 pm - Hi markr, thanks again.
In response to parts 1 and parts 3, these still yield some issues with more 'assorted' groups been classed as more 'dissassorted' but I'll... (view)
Tue 22 Jul, 2014 05:18 am - Thanks, these are very usable solutions to the problem when a 50/50 ratio is assumed. I prefer no.1 and no.3, as I think no.2 would have a slight problem with groups with odd numbers in, whereby... (view)
Mon 21 Jul, 2014 11:57 pm - Hi
Initially I was wanting the assortment of the actual groups too, to use these values in later models. However, yes, I also need the assortment propensity of the sampled population, in terms of... (view)
Mon 21 Jul, 2014 01:51 am - From the questions you are asking I think we are thinking about this in a very similar way, which is very good. Apart from, this point, which I hope to address (or understand where you are coming... (view)
Sun 20 Jul, 2014 10:33 pm - good question, and yes, a group which initially appears more 'balanced' could actually be ranked as less assorted than a group which appears 'less balanced', based on... (view)
Sun 20 Jul, 2014 04:14 am - Hi Mark
Thanks very much for your reply
Yes, 1M/ 1F (from 1:1) definitely does not show any assortment (i.e. propensity for 'males to be with males' and 'females to be with... (view)
Sat 19 Jul, 2014 10:01 am - Hi
I need a formula that returns a value representative of the amount of ‘assortment’ a group shows. The groups are made up of individuals, all of a binary class (e.g. male or female),... (view)
