Member since April 1, 2006

dimatt

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dimatt
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Wed 12 Apr, 2006 03:40 pm - ^ I had this same problem in class almost a month ago. Sorry i really cant remember much from it now though. I can only recall using the orthogonal through the process, i think :s Sorry. (view)
Tue 11 Apr, 2006 03:50 pm - [img]http://img.photobucket.com/albums/v616/-cadre-/tada.jpg[/img] This did take me a while to find ;) (view)
Tue 11 Apr, 2006 01:57 pm - And thank you for putting me on the right track to getting the answer ;) (view)
Tue 11 Apr, 2006 01:35 pm - ^^ it actually turned out that i was going about it totally the wrong way. You can use 2 of the equations that freeduck mentioned and the third is representative of the equilateral triangle formed... (view)
Sun 2 Apr, 2006 06:40 am - Yes but the question is asking for an independent equation for each value that determines the 'area of each region'. That to me tells me that they are asking for an equation that will get... (view)
Sat 1 Apr, 2006 06:34 pm - Yes, but the equations have to be independent of themselves. So you cant just say z= 36- (y+x). Like for the formula for x i have gotten: x=(36-(9√3)-6π)cm^2 So i also need to find... (view)
Sat 1 Apr, 2006 10:58 am - My class was given a few challenge problems as a review for an up and coming test. It is as follows: The challenge is to obtain three independent equations in x, y, and z that can be solved to... (view)
 
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