Member since May 9, 2005

Capt Piet

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Capt Piet
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DEs
Mon 9 May, 2005 02:19 pm - It looks fine to me. (view)
DEs
Mon 9 May, 2005 09:03 am - I need to answer this question. Can you help? [1 0 1] [e^t ] X' = [0 0 1] X + [0 ] [0 0 2] [e^-t] X and X' are vectors, obviously. I got [t]... (view)
 
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