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Can this be solved?

 
 
Reply Sat 8 Jan, 2022 01:04 am
Jim played 10,000 games, and won 62% of the time, or 6200 games.
Suppose he improves his skill and now wins consistently 64% of the time. How many total games will he have to play before his overall average reaches 63%?
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Type: Discussion • Score: 1 • Views: 318 • Replies: 5
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Susan G
 
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Reply Sat 8 Jan, 2022 02:37 am
@SouthernAtHeart,
He will need to play 10,486.43 games. Please keep in mind I have not taken a math class in 48 years so I could be wrong Wink
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Susan G
 
  2  
Reply Sat 8 Jan, 2022 03:26 am
I calculated that he must play 322.58 more games ( or win a total of 6522.58 games) to bring up his wins to 64%. Btw that means he has played 10,322.58 games right? To then bring his wins down to 63%, he must lose 163.85 more games to bring his total number of games to 10,486.43 (322.58+163.85=486.43 more games and 6522.58 is approximately 63% of 10,486.43) I hope this helps Wink)
SouthernAtHeart
 
  1  
Reply Sat 8 Jan, 2022 09:25 am
@Susan G,
Wow! That was quick!
Can you show me the formula for how you calculated that? I like math, but it’s been too long! LOL 33 years
Thanks!
SouthernAtHeart
 
  1  
Reply Sat 8 Jan, 2022 09:40 am
@SouthernAtHeart,
I’m not sure that was correct,
If he plays 328 more games, but he only wins 64% of the time, he would only win 210 of those games, so
6200 + 210 / 10,000 + 328 = 0.6208

If seems like it should be something like this, but I don’t know how or if you can solve it mathematically. I’m sure you can somehow.

6200 + (.64 x Z) / 10,000 + (.64 x Z) > 0.63
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ekename
 
  2  
Reply Sat 8 Jan, 2022 09:05 pm
@SouthernAtHeart,
If 10,000 games are played at 62% then you need to play 10,000 more games at 64% to have an overall 63% average.

0.62 x 10,000 + 0.64 x (new games) = 0.63 x (10,000 + new games)
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