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Thu 20 May, 2021 09:51 pm
Use the intercept form to find the general form of the equation of the line with the given intercepts. The intercept form of the equation of a line with intercepts (a, 0) and (0, b) is (x/a) + (y/b) = 1, where a ≠ 0, b ≠ 0.
1. x-intercept: (−3, 0)
y-intercept: (0, 4)
2. Point on line: (−3, 4)
x-intercept: (d, 0), d ≠ 0
y-intercept: (0, d), d ≠ 0
I need hints for questions 1 and 2.
@nycdad,
1) They give you A = -3 and B = 4, just plug into the equation.
2) In the general form of the equation you have, both a and b are "d", so the challenge is to find what d is. Substituting into the general form, you have (x/d) + (y/d) = 1 so (x+y)/d=1. Plug in the point you are given to solve for d.
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