here's a fun proof that 7 =14

most proofs that result in this kind of nonsense usually sneak in a division by zero.......not the case here, which makes it a bit unique

The derivation of x+x+x (x times) is NOT 1+1+1+1....(x times). Because "x times" is NOT derivated.

Not to mention, 14=5

I don’t see the fun.

I'm going to say this is close enough.....we are not dealing with continuous functions and hence not differentiable

I don't think so.

X + x + x ... (x times) is but an odd way to write "x times x", usually shortened x * x or x^2.

Y = x^2 is a continuous function.

we are dealing with integers on the left side of the equation... I agree f(x)=x^2 is continuous and differentiable.....but consider g(x)= x+x+x+x..............x times. We know g(x)= x^2 is true if x is an integer....is it true if x=, say, pi ? is it true if x = -4.8 ?

For those that remember the definition of a derivative (lim as h goes to zero of (g(x+h)-g(x))/h, try to take the derivative of g(x) and it will fall apart.

However, if you think g(x) is differentiable, then there is nothing wrong with the proof and indeed, 7 does in fact equal 14

Okay, but your problem statement does not explicitly limit x to integers.

Correct, I worded the proof to mislead .... As an aside, I can also 'prove' all triangles are isosceles if interested