what additional volume of liquid (in c.c.) can be put into the beaker?

Check out the temperatures you give. It doesn't make sense.

Quote unimpo:


Fresco is right. The question makes no sense as written since beaker and liquid going from 33.30 C to 50 C are not being cooled, they are being heated.
Recheck the figures you posted.

OK, this is my best guess on a topic new to me.

The temperature drops from 33.3 degrees C to 5 degrees C.

"The volumetric expansion co-efficient of ethanol is 0.00109 per degree C."
https://www.engineeringtoolbox.com/cubical-expansion-coefficients-d_1262.html

In the equation below I assumed you accidentally put one too many zeroes in your figure for the volume expansion co-efficient.

"The change in the units volume when temperature changes can be expressed as:
dV = V0 β (t1 - t0)
where
dV = V1 - V0 = change in volume (m3, ft3)
β = volumetric temperature expansion coefficient (m3/m3 oC, ft3/ft3 oF)
t1 = final temperature (oC, oF)
t0 = initial temperature (oC, oF)"

Thus

dV = (456) x (0.00109) x (-28.3) = 14.0662 cm^3

(as per the formula above using the toolbox calculator)



https://en.wikipedia.org/wiki/Thermal_expansion
"For isotropic materials the volumetric thermal expansion coefficient is three times the linear coefficient."
Glass is isotropic.

The linear expansion co-efficient of alpha times 10^-6 (3.2X10-6K-1) has an immaterial effect of the capacity of the beaker (0.13 cm^3).

The engineering toolbox site includes calculators and worked examples on volume changes to liquids and linear changes to materials.