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Wed 18 Mar, 2015 11:43 am
The common distance of the stars , by Aetzbar ………………………………..……………………………1
Countlees stars moving infinite space.
The stars are combined according to the idea of a central star , and ather stars revolving
around it. Each star is a central star and ather star, at the same time.
Kepler discovered the univerce formula D^3 : T^2 = P ( P is number )
D – The distance of ather star from central star.
T – Time that ather star rotates around a central star.
Newton : Each star has its material quantity ( M – view Newton)
M determines P that appesrs in Kepler's universe formula.
If M will increase 5 times,then either P increase 5 times.
How to get the P of earth ? with Kepler's universe formula. D^3 : T^2 = P
The earth is a central star for the moon.
Moon is far from earth 384000 km, and time it orbited the earth 672 hours.
P = 384000^3 : 672^2 = 1.25*10^11
P of earth is determined by M of earth.
There are an infinite number of combination of D and T ,if selected D ,the formula tell us T. If you want to send a satellite to earth, a height of 88000 km ,time it will circle the earth,
predetermined. T = root of ( 88000^3 : 1.25*10^11) = 74 hours
Finding p of the Sun.
The Sun is a central star for the earth (with the moon moves around)
P is obtained by the distance ( Earth – Sun) and time of 1 year in hours.
P of Sun = 429*10^14 P of the Sun determined by M of the Sun.
The common distance of the stars , by Aetzbar ………………………………..……………………………2
Galileo introduced an imaginary experiment , in which a ball falls to the entrance of a
Tunnel that reaches the other side of the earth. This ball will illustrate a pendulum
Movement , between the two openings of the tunnel.
The cycle time will be 1.4 hours. Marked ]T[
P of earth and ]T[ of earth ,determines by M of earth.
The common distance of the stars
As we move away from a star, lap time around it will grow. ( T increases) Therefore ,the
Equality T = ]T[ must appear each star, at some distance from the center of the star.
So that all the stars in the universe will be in harmony, need only a single distance which appears the equality T = ]T[
How do we find the common distance of the stars ?
Since M of star determines its P and ]T[ , must be a connection between P and ]T[
The connection is P* ]T[^2 = number
This connection will reveal the common distance of the stars.
P of earth = 1.3*10^11 and ]T[ of earth = 1.4 hours
1.3 * 10^11)*1.4^2 = 2.5 * 10^11 )
( D^3 : T^2) * [T[^2 = 2.5 * 10^11
T = ]T[
D^3 = 2.5*10^11
D = 6300 kilometers
The common distance of the stars = 6300 km
Satellite close to the ground, makes a complete revolution in 1.4 hours.
]T[ of earth is 1.4 hours.
Earth space are within 6300 km from the center of the earth.
The common distance of the stars , by Aetzbar ………………………………..……………………………3
6300 km is a Natural Physical Constant.
The equality of times T = ]T[ appears at 6300 km from the center of each star.
Each star has its unique M and unique ]T[
M* ]T[^2 = constant
We live in a place of equality times
]T[ of Sun is 8.7 seconds
In distance of 6300 km from the center of the Sun, T is 8.7 seconds
]T[ of Earth is 5050 seconds
In distance of 6300 km from the center of the Earth, T is 5050 seconds
6300 km is common distance of all stars
A new physical theory belongs to the kingdom of stars. By Aetzbar -------------------- 1
The stars are moving and never stop.
Stars move like a screw – turn and advanced. (Aetzbar's view)
Each star is a central star and side star, at the same time.(Copernican view)
The Sun is a central star for the Earth ,and Earth is a central star for the Moon.
The Earth is a side star for the Sun, and the Moon is a side star for the Earth.
Side star revolves around central stare, with lap time T
Let's say that the sun is a point and earth as a point
If we move away from the sun,the distance D will increase from zero km to infinity km
lap time T will increase (from zero hours to infinity hours)
If we move away from the Earth,( D will increase from zero km to infinity km )
lap time T will increase (from zero hours to infinity hours)
The Sun has a unique fit between D to and T.
The Earth has a unique fit between D and T.
Each star has its unique fit between D and T.
Kepler fined the formula of all stars D^3 : T^2 = P
P is a unique number of star, that represents a unique fit between D and T.
How to get the P of earth ?
The earth is a central star for the moon.
Moon is far from earth D = 384000 km, and time it orbited the earth T = 672 hours.
P of Earth = 384000^3 : 672^2 = 1.25*10^11
A new physical theory belongs to the kingdom of stars. By Aetzbar -------------------- 2
Finding p of the Sun.
The Sun is a central star for the earth (with the moon moves around)
P is obtained by the distance ( Earth – Sun) and time of 1 year in hours.
P of Sun = 429*10^14
Newton's view
Each star has its Material quantity M
Newton presented the relationship between M and P ( M1 : M2 = P1 : P2 )
After P and M of star , reaches ]T[ of star. ( ]T[ is Cycle Time of star)
Galileo introduced an imaginary experiment , in which a ball falls to the entrance of a
Tunnel that reaches the other side of the earth. This ball will illustrated a pendulum
Movement ( cycle time = 1.4 hours ) between the two openings of the tunnel.
Glileo's experiment determines the Cycle Time of earth ( 1.4 hours)
each star has its Cycle time.
Natural connection
M of star determines its ]T[ , by the formula M* ]T[^2 = K (Aetzbar's view)
Because M1 : M2 = P1 : P2
We have the formula P* ]T[^2 = K
According to P of Earth and ]T[ of Earth , K = 2.5*10^11
With the formula P* ]T[^2 = 2.5 *10^11 can calculate ]T[ of Sun = 8.7 seconds
A new physical theory belongs to the kingdom of stars. By Aetzbar ---------------3
Predetermined distance of 6300 km , for T = ]T[
The formula P* ]T[^2 = 2.5*10^11
is the formula (D^3 : T^2)* ]T[^2 = 2.5 * 10^11
The formula shows that the situation of T = ]T[ appears at the distance of 6300 km, from
the center of each star.
D^3 = 2.5*10^11
D = 6300 km
Why ?
Why 6300 km from the center, and not 7214 km from the center ? The formula of
Kepler D^3 : T^2 = P is also suitable for 7214 km , 12879 km , 670 km , and so on
Why 6300 km ?
There is no choice but to accept the next miraculous story.
Kingdom of the stars chose a distance of 6300 km.
Then metaphysical law was passed,
Equality T = ]T[ will only appear, within a 6300 km from the center of star.
Earth was chosen to represent the law.
Radius of Earth is 6300 km and Cycle Time of Earth is 1.4 hours.
Satellite moves closer to Earth, makes a complete revolution in 1.4 hours.
Cycle Time of the Sun is 8.7 seconds.
Suppose the Sun as a point, and a satellite around her ,within 6300 km
The lap time T will be 8.7 seconds.
The result of unique P to each star, is due to the law of stars kingdom.
@aetzbar,
Stars are a lot farther away than 6300 km. Hell, the sun is A LOT farther away than that. You might want to Google a few terms like light-year and speed of light. And a bunch of others that I don't have time to get into right now because I really don't feel like teaching elementary physics in a forum post.
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