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The mathematical structure of a "Peptide". Let's have a Pep talk.

 
 
Reply Sun 23 Nov, 2014 02:25 pm
The mathematical structure for "Peptide": http://upload.wikimedia.org/wikipedia/commons/a/a4/Beta-peptides.png

N (Nitrogen) = 28/56.028

O (Oxygen) = 32/64

H (Hydrogen) = 4/4.0316

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28 + 32 + 4 = 64 (8x8 = 64). -----> 316 x 4 = "1264" - 64 x 2 = 128; 128 x 2 = 256; 256 x 2 = 512; 512 x 2 = "1024, a.k.a how many bytes equal a mega byte)

Numbers before the decimal are 56 + 4 + 64 = 124. 1.24 x 1.618 = "2.00632". Half of 632 is "316" <-----. 16 x 3 = "48". 48 x 2 = 96. ------> "O = 32/64".

The numbers after the decimal are 28 + 316 = "344". 3 x 44 = 132. 1.32 x 1.618 = "2.13576". Half of 12576 is "6788" <------. 788 x 6 = "4728". This is a 72 and a 48. Together that is 120. 120 is 1/3 of a full circle. What number is dominate in this formula: ---> "64". 316 x 4 = "1264" <--- Genius.

I am not done yet, I still have to multiply the numbers on the right side by 1.618:

5.628 x 1.618 = "9.106104"

6.4 x 1.618 = "10.3552".

4.316 x 1.618 = "6.983288". <--- 5/9 ratio. Half of 983288 is 491644. Half of that is 245822. Half of that is ---> "122911" <-- Genius. That is a "33". 122 + 911 = "33". And I said this was a 1/3 formula before I unconventionally multiplied the numbers with the Golden Ratio. "Half of 12576 is "6788" <------. 788 x 6 = "4728". This is a 72 and a 48. Together that is 120. 120 is 1/3 of a full circle. What number is dominate in this formula: ---> "64". 316 x 4 = "1264" <--- Genius."

12 + 64 = 76.

7 x 6 = "42".
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Type: Discussion • Score: 1 • Views: 942 • Replies: 2
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Pearlylustre
 
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Reply Sun 23 Nov, 2014 04:13 pm
@One Eyed Mind,
I still don't understand why you're not sending all this stuff to universities and scientific journals if you're such a genius.
One Eyed Mind
 
  1  
Reply Sun 23 Nov, 2014 10:05 pm
@Pearlylustre,
Do I really have to start looking for the timelines between other discoveries from other geniuses?

Even I said "it took you 3 years to figure this out?".
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