Derivative

Use the chain rule.

Sin x 3 = Troilism.

If f(x) = sin (x^3 )
let u = x^3
du/dx = 3x^2
df/du = cos u
df/dx = du/dx times df/du = (3x^2 ) times cos u
Then df/dx = (3x^2) cos ( x^3)

Triolism and errorism notwithstanding.

Is this actually in the Kama Sutra? Or are you just making this up?

I've just re-read the thing cover to cover and can't see this anywhere.

I now know what I'll be doing this weekend though....

It's in the addendum , Kamasutran chain rules, you've obviously gone off on a tangentx when you were really secantx.

Take three ∫ tan³(x) sec(x) dx = sec³(x)/3 - sec(x) + C and call me on your next trip.