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Mon 4 Feb, 2013 12:10 am
On New Year's Eve, the probability of a person having a car accident is 0.09. The probability of a
person driving wh)le intoxicated is 0.32 and probability of a person having a car accident while
intoxicated is 0.15. What is the probability of a person driving while intoxicated or having a car
accident?
(a) 0.32 (b) 0.15 (c) 0.26 (d) 0.28 (e) Not enough data
PLEASE TELL ME THE WAY TO SOLVE IT
@Dchaser,
Dchaser wrote:
On New Year's Eve, the probability of a person having a car accident is 0.09. The probability of a
person driving wh)le intoxicated is 0.32 and probability of a person having a car accident while
intoxicated is 0.15. What is the probability of a person driving while intoxicated or having a car
accident?
(a) 0.32 (b) 0.15 (c) 0.26 (d) 0.28 (e) Not enough data
PLEASE TELL ME THE WAY TO SOLVE IT
No way to calculate the probability of a person driving a car. I think you're going to have to restate the question. In fact, the first given is a little shaky, since we don't know that all persons on New Year's eve will be driving.
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