Thu 10 Aug, 2006 08:14 am - a - side of the square
b - side of the triangle
r - radius of the circle
a,b,r > 0
a^2=1.5 * pi * r^2 - given -> r=a/sqrt(1.5 * pi)
a^2= 1.75 * sqrt(3)/4 * b^2 - given ->b =... (view)
Wed 12 Jul, 2006 11:06 am - Congratulations! You have guessed correctly in the Lenny Conundrum game (round 174). You have won 2206 NP!
Because you were in the first 250 to guess correctly, you also have been awarded a... (view)
Thu 6 Jul, 2006 06:36 am - the diameter squared is 250 sq.cm.
the area is (d/2)^2*pi=d^2*pi/4
the area of the 4 white squares inside - 5^2 * 4 sq.cm.
250*pi/4 - 25*4 = 96.349540849362077403915211454969 sq.cm. ~ 9635... (view)
Thu 4 May, 2006 08:27 am - sphere has a radius r and centered on the origin, the volume in question goes from -r to 2 (6.5 depth) on the x axis.
the radius of the cylinder - (r^2-x^2)^1/2
the area of the cylinder -... (view)
Wed 19 Apr, 2006 11:20 pm - fmorel got it right - 45
1/5x+18=1/3x => x=9*15
t'morrow = yesterday * 4 = 4* x/3
t'morrow - t'day = 4/3x - x = 1/3x=9*5 = 45
I took me about as long as this page was loading... (view)
Wed 19 Apr, 2006 11:19 pm - fmorel got it right - 45
1/5x+18=1/3x => x=9*15
t'morrow = yesterday * 4 = 4* x/3
t'morrow - t'day = 4/3x - x = 1/3x=9*5 = 45
I took me about as long as this page was loading ;P (view)
Wed 29 Mar, 2006 09:42 pm - Total weight of five grundos (a - heaviest, e - lightest) a+b+c+d+e = sum of all 10 measurements / 4 (every single grundo was weighted exactly 4 times) = 606
a+b - the highest available weight =... (view)
Wed 29 Mar, 2006 07:57 pm - go back to pages 203 and 204 for hints. after you figured out the weight of the middle one you want to know which weight is sum of the heaviest grundo and the one in the middle. (view)
