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Math Help - Binomials and Trinomials

 
 
Reply Sun 9 Apr, 2006 08:30 am
how would i narrow this down to a trinomial or a binomial. I really have no idea.

(x+y)(x+y)
 
View Profile markr
 
  1  
Reply Sun 9 Apr, 2006 09:12 am
do the multiplication
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View Profile Lash
 
  1  
Reply Sun 9 Apr, 2006 10:56 am
Do you know FOIL?
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  1  
Reply Thu 13 Apr, 2006 12:55 pm
(x+y)(x+y)

is a multiplication function: the quantity of (x+y) times the quantity of (x+y). You do that by multiplying both terms (the x and y) by both terms in the other set (the second x and y) and adding up the results.

X times X (the 1st terms in the 1st parentheses times 1st term in the second parentheses) = x^2

X times Y (the first term in the 1st parentheses times 2nd term in the 2nd parentheses) = xy

Y times X (the second term in the 1st parentheses times the 1st term in the 2nd parentheses) = xy

Y times Y (the second term of both parentheses multiplied together) = y^2

add them up to get:

x^2+2xy+y^2

This can't be simplified by adding anymore, and the items are separated by addition (subtraction is also acceptable), which makes them 'terms.' There are three, so this is a trinomial.

A binomial would be an equation with two terms, like

x+y

or something to that effect.


Hope that helped.
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View Profile testify
 
  1  
Reply Thu 13 Apr, 2006 01:21 pm
Wow we're doing that in my algebra class too. xD
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View Profile masterJ
 
  1  
Reply Fri 14 Apr, 2006 09:50 am
foil
it is called foiling

(x+y)(x+y)
is equivlent to
x*(x+y)+y*(x+y)
when we do this we get
(x^2+xy)+(yx+y^2)
adding the like terms gives us
x^2+2xy+y^2
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View Profile Baph
 
  1  
Reply Fri 14 Apr, 2006 06:48 pm
How do you dudes connect the green advertising links - sales pitch from hell? Only joking I know a site like this is not "easy"to fund.

Would appreciate knowing how to do it though.
0 Replies
 
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Reply Fri 14 Apr, 2006 10:22 pm
E-mail the administrators. Jespah or Craven de Kere are the guys to ask that question.
0 Replies
 
  1  
Reply Sat 15 Apr, 2006 02:19 am
Baph, welcome to A2k Smile

you can also ask your question by starting a new topic here in the Web Development Forum...
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