I need help with limits

Have you looked at the graph of f?

Eliz.

Yea i looked at the graph of f, but what i need help with is how to set up the limit

You're doing an epsilon-delta type proof?

Eliz.

f( x )= -2 / (2x+1)(3x+6)
the function is discontinue only when [(2x+1)(3x+6)=0] that means only when (2x+1)=0 or (3x+6)=0 that means only when x=-0.5 (a) or -2 (b)
so you need to calculate the limit on both a and b
on a: f(b)=-2 / (-3)*0 = +inf.
on b: f(a)=-2 / 0*(4.5) =-inf.


excuse me on my english, i learn maths in french

Let me try!
An equation goes discontinuous when the value of the function goes infinite

f( x )= -2 / (2x+1)(3x+6)


Here the value can go infinite ONLY when the denominator is 0


(2x+1)(3x+6) = 0

x = -1/2

or x = -2