NeoPets Riddles (Lenny Conundrums) and Answers Here

so did anyone get the answer right?

the answer is year 8...

That is exactly what I did. And this time it showed up first. I wanted to see if anybody read my message

"Year 8"? That's what they were wanting?



Any clues what that means...?

Eliz.

That's the current year in Neopia, but they haven't specified yet how to arrive at that [besides GUESS]

How do you know that the answer is year 8?

lenny last week
the results was posted on the game page under week 148.

New LC
8k - 5n = 8r
2u + o = 108
2m + 10d = 3c
2u + 3r= 10m
10b - L = 8m
3k - 4i = 2i
3n - 3o = c
o - c = 4d
3n - 7d = 10m
2d + 2e = 3b
9n - 9r = 8i
6b + 3c = 14m
4y - 2m = 6u

L + e + n + n + y + c + o + n + u + n + d + r + u + m = ???

Lenny Conundrum
Sorry! I'm trying to figure it out.. but im TERRIBLE at math!!!


The only idea I have it to work it out on excel or a spread sheet!

you can start with the only base number given of 189 and work out that formula. that should help u get some of the letters going for the other problems

That's what I've been trying to do. It's slow going though. I'm maybe halfway through.

b = 20
c = 30
d = 6
e = 24
i = 36
k = 72
L = 80
m = 15
n = 64
o = 54
r = 32
u = 27
y = 48

80+24+64+64+48+30+54+64+27+64+6+32+27+15 = 599

I got a MUCH lower number than that....

After some rearrangement, we have the following system of equations:

. .. . 0b + 0c + . 0d + 0e + 0i + 8k + 0L + .0m - .5n + 0o - .8r + 0u + 0y = . . 0
. .. . 0b + 0c + . 0d + 0e + 0i + 0k + 0L + .0m + 0n + 1o + 0r + 2u + 0y = 108
. .. . 0b - .3c + 10d + 0e + 0i + 0k + 0L + .2m + 0n + 0o + 0r + 0u + 0y = . . 0
. .. . 0b + 0c + . 0d + 0e + 0i + 0k + 0L -.10m + 0n + 0o + 3r + 2u + 0y = . . 0
. . .10b + 0c + . 0d + 0e + 0i + 0k - .1L - . 8m + 0n + 0o + 0r + 0u + 0y = . . 0
. .. . 0b + 0c + . 0d + 0e - .6i + 3k + 0L + .0m + 0n + 0o + 0r + 0u + 0y = . . 0
. .. . 0b - .1c + . 0d + 0e + 0i + 0k + 0L + .0m + 3n - .3o + 0r + 0u + 0y = . . 0
. .. . 0b - .1c - .. 4d + 0e + 0i + 0k + 0L + .0m + 0n + 1o + 0r + 0u + 0y = . . 0
. .. . 0b + 0c - .. 7d + 0e + 0i + 0k + 0L -.10m + 3n + 0o + 0r + 0u + 0y = . . 0
. .. .-3b + 0c + . 2d + 2e + 0i + 0k + 0L + .0m + 0n + 0o + 0r + 0u + 0y = . . 0
. .. . 0b + 0c + . 0d + 0e - .8i + 0k + 0L + .0m + 9n + 0o - .9r + 0u + 0y = . . 0
. .. . 6b + 3c + . 0d + 0e + 0i + 0k + 0L -.14m + 0n + 0o + 0r + 0u + 0y = . . 0
. .. . 0b + 0c + . 0d + 0e + 0i + 0k + 0L - . 2m + 0n + 0o + 0r - .6u + 4y = . . 0

I set up the system of thirteen variables in thirteen equations as a matrix, and used solver software to obtain the following:

. . . . .b = 20
. . . . .c = 30
. . . . .d = 6
. . . . .e = 24
. . . . .i = 36
. . . . .k = 72
. . . . .L = 80
. . . . .m = 15
. . . . .n = 64
. . . . .o = 54
. . . . .r = 32
. . . . .u = 27
. . . . .y = 48

In other words, the software echoes the solution markr proposed.

Eliz.

["Year 8"? That's what they were wanting?

Shocked

Any clues what that means...?

Eliz.]

Year 8 because it was round 148.

1 is for January
4 is the day they judge the lenny conundrum
8..year 8

You only added n once in lenny, so the answer is 663

LC answer
[You only added n once in lenny, so the answer is 663]

No, they were right. There are 14 characters in 'Lenny Conundrum' and they had 14 numbers added up to 599.

Re: New LC
hi im new here.
and i was thinking that maybe the LC is different for different people now i dunno cause elybelly posted



but mine on the site is



some numbers are different..



ok actually i think its just rearranged. i dunno

Re: New LC
It appears that the system of equations may have been tweaked. Looking at the first two equations, we have:



Since no equation other than the second one in each system has a strictly numerical term (that is, a term containing no variable), this new system cannot be simply a "rearrangement" of the original one, since (I'm pretty sure) no combination of the original equations would have created that new second equation.

However, before anybody panics, plug the original solution values for each letter into the new system's equations. As long as all the new equations work out to be true statements, the original solution of "599" is still valid.

For instance, the new third equation, "5d + 2c = 6m", evaluates as 5(6) + 2(30) = 30 + 60 = 90 for the left-hand side and as 6(15) = 90 for the right-hand side, so the original system's variable values work in the new third equation. Test all the other new equations, to verify the original solution.

Eliz.

o ok i tested them there right

thanks