0
   

Advanced Physics

 
 
kemar
 
Reply Sun 24 Jan, 2016 10:53 am
2 particles of mass 0.2kg and 0.3kg are placed 0.15 meters apart. A third particle of mass 0.05kg is placed between them on the line joining the first two particles. Calculate:
A) The gravitational force acting on the third particle if it were placed 0.05 m from the 0.3...... I answered that one already the real problem that I am having is with question B.
B) Where along the line should it be placed for no gravitational force to be exerted on it. -----would really appreciate some help with this question
  • Topic Stats
  • Top Replies
  • Link to this Topic
Type: Question • Score: 0 • Views: 675 • Replies: 2
No top replies

 
fresco
 
  1  
Reply Sun 24 Jan, 2016 11:29 am
@kemar,
B.
m1.m3/d^2 =m2.m3/(0.15 - d)^2

Solve for d
kemar
 
  1  
Reply Sun 24 Jan, 2016 12:27 pm
@fresco,
Thanks!
0 Replies
 
 

Related Topics

New Propulsion, the "EM Drive" - Question by TomTomBinks
The Science Thread - Discussion by Wilso
Why do people deny evolution? - Question by JimmyJ
Are we alone in the universe? - Discussion by Jpsy
Fake Science Journals - Discussion by rosborne979
Controvertial "Proof" of Multiverse! - Discussion by littlek
 
  1. Forums
  2. » Advanced Physics
Copyright © 2024 MadLab, LLC :: Terms of Service :: Privacy Policy :: Page generated in 0.06 seconds on 04/25/2024 at 12:11:09