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My problem

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Porter264
 
Reply Sun 4 Aug, 2013 06:29 am
P(s) = .07
P(r) = .01
P(H | s,r) = 1
P(H | not s,r) = .9
P(H | s,not r) = .7
P(H | not s, not r) = .1

What is the probability P(r and s) =
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