Thinking Fast and Slow probability question

BM.

I am looking at this problem. It is poorly worded I am trying to figure out what the second part means.

I think there is a missing piece of information here needed for Baye's law, namely the percentage of students who are "like Tom W'.

Let me look a little more.

Yep, unless I am really misunderstanding the question then there is not enough information here to solve it.

Bayes law say P(A|B) = P(B|A) * P(A)/P(B)

A is Computer science
B is TomLike (i.e. someone with the "description of Tom W")

So P(A|B) is read "the probability of Computer Science given TomLike". In other words this is the chance that someone who is TomLike is in Computer science.

P(B|A) is the probability that someone who is in Computer Science is TomLike. We have to figure out what this is from that strangely worded second part.

P(A) is the chance that someone is in computer science. This is clearly 3%.

P(B) is the chance that someone is TomLike. This is the problem, there is apparently no way to figure this out even if we can what the heck they mean for by that strangly worded phrase for P(B|A).

I don't think this can be solved.

Found this in the back of the book:

"For the hypothesis that Tom W is a computer scientist, the prior odds that correspond to a base rate of 3% are (.03/.97 = .031). Assuming a likelihood ratio of 4 (the description is 4 time as likely if Tom W is a computer scientist than if he is not), the posterior odds are 4 x .031 = 12.4. From these odds you can compute that the posterior probability of Tom W being a computer scientist is now 11% (because 12.4/112.4 = .11)."

By the way, I found this by googling:

Thinking Fast and Slow computer scientist is now 11%

and found it in Google Books.

Markr,

I think this math is simply wrong, and I think I can prove it.

Let's assume 10000 graduate students of which 300 are Computer scientists (that makes 3%).

Let's say 4 people who are Computer Scientists are TomWLike and 1 is not TomWLike (that makes it 4 times as likely that Tom is a computer scientist than not).

Now I think I have met all the inputs to the problem (base rate and likihood ratio), where the heck do you get 11%?

It is possible that I am just misunderstanding the question, but if you want to defend this reasoning then please do it with real numbers.

I see the math and it works. But then the author says change the base rate to 80 % and the new answer is 94.1. Given his formula I can't make that work.

Wardjames, can you show me how the math works with a real example (i.e. 10,000 students)?

I'm not defending anything. I merely posted what I found in the back of the book.

I'm not sure what a "real numbers" scenario means. But too my surprise (I'm not a math person) I used an Excel spreadsheet and got both sets of numbers to work:

.03 (prior probability) * 4 (conditional probability) = .12 .97 (prior probability) * 1 (conditional probability) = .97.

.12/(.12+.97) = 11


.08 * 4 = 3.2 .2 * 1 = .2

3.2/(3.2 + .2) = .941

OK sure, so you can get numbers that the author gave you to match numbers that the author got. But what does it mean? You probably did the same calculation that the author did, but that doesn't mean the calculation isn't bogus.

And it certainly doesn't help me, or anyone else, understand the calculation.

I gave you Bayes theorem. It would help if someone could explain why the calculation you did has anything to do with Bayes. I admit that it might, but I have done these calculations before and I don't see it.

I haven't digested this, but it references Bayes' Theorem in forms that are different than the "standard" form you provided. It seems to use language that will explain the usage in the stated problem.

http://plato.stanford.edu/entries/bayes-theorem/