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Fri 22 Aug, 2008 02:15 pm
Using the standard Lorentz time-dilation formula, I calculated that one reference frame must be passing another reference frame at approximately .866 x c (the speed of light) in order for any observer in each of the two reference frames to think that the clocks in the other reference frame were running half as slow. Is this correct?
This q's way beyond my grade level.
Wikipedia says you're right:
Code:Speed Lorentz factor Reciprocal
β = v / c γ 1 / γ
0.010 1.000 1.000
0.100 1.005 0.995
0.200 1.021 0.980
0.300 1.048 0.954
0.400 1.091 0.917
0.500 1.155 0.866
0.600 1.250 0.800
0.700 1.400 0.714
0.800 1.667 0.600
0.866 2.000 0.500
0.900 2.294 0.436
0.990 7.089 0.141
0.999 22.366 0.045
http://en.wikipedia.org/wiki/Lorentz_factor
im still stuck on the word Using
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