math problem

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A friend emailed me a math problem. I don't know the answer to this problem and I was wondering if anyone here can solve it.

X = 3-Y
Y = 12/X
Z = 1/X + 1/Y

solve for Z without rounding or truncating any decimals

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[+1] - raprap - 03/18/2008[size=7][color=orange]x=3-y so x+y=3 y=12/x so xy=12 z=1/x+1/y completing fractions z=y/(xy)+x/(xy)=(x+y)/(xy) & from above z=3/12=1/4[/color][/size] Hope this helps Rap
[+1] - TTH - 03/18/2008Thanks raprap :D

[size=7]x=3-y
so
x+y=3

y=12/x
so
xy=12

z=1/x+1/y
completing fractions
z=y/(xy)+x/(xy)=(x+y)/(xy)
& from above
z=3/12=1/4[/size]

Hope this helps

Rap

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Thanks raprap Very Happy

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math problem

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